The Big Ten revealed on Tuesday that Ohio State will be playing against Indiana on Oct. 17 in Bloomington, Ind.
The Hoosiers won the program’s first-ever national championship on Monday, finishing a historic 16-0 season that included winning the Big Ten championship for the first time since 1967 and quarterback Fernando Mendoza winning the first Heisman Trophy in school history.
The Buckeyes will be looking for revenge after Indiana was able to beat them in the Big Ten championship on Dec. 6, keeping Ohio State from its first conference title since the 2020 season.
Both teams will look very different than they did last season, with Ohio State losing many impactful defensive starters to the NFL, along with wide receiver Carnell Tate. Julian Sayin — who was fourth in Heisman voting — will still be under center for the Buckeyes.
The Buckeyes game against the defending national champions does not have a scheduled time yet. It’s the only conference game with a set date, but Ohio State’s nonconference slate is fully set already. The season will begin on Sept. 5 against Ball State at home before the Buckeyes go on the road to finish the second half of a home-and-home series against Texas on Sept. 12. The last nonconference matchup is on Sept. 19 against Kent State.
The conference opponents Ohio State will play have already been revealed with no dates for the games yet. The Buckeyes will also play away games against Iowa, Nebraska and USC. They have home games against Illinois, Maryland, Michigan, Northwestern and Oregon.
The rest of the Big Ten schedule will be revealed on Jan. 27 at 5:30 p.m. on Big Ten Network.
